ci(mindmodel): add report-only mindmodel validation workflow

main
Sven Geboers 1 month ago
parent d1faf2b3e4
commit 540099f2b7
  1. 47
      .github/workflows/mindmodel-validation.yml
  2. 26
      tests/ci/test_workflow_exists.py

@ -0,0 +1,47 @@
name: mindmodel validation
on:
push:
branches: [ main ]
pull_request:
branches: [ main ]
jobs:
validate:
runs-on: ubuntu-latest
steps:
- name: Checkout
uses: actions/checkout@v4
- name: Set up Python
uses: actions/setup-python@v4
with:
python-version: '3.x'
- name: Install development dependencies (if present)
run: |
python -m pip install --upgrade pip
if [ -f requirements-dev.txt ]; then
pip install -r requirements-dev.txt
else
echo "requirements-dev.txt not found, skipping"
fi
- name: Run mindmodel validator (report-only)
if: ${{ always() }}
run: |
# Make this step report-only: run the validator but always exit 0 so PRs are not blocked
set +e
if [ -f .mindmodel/manifest.yaml ]; then
python scripts/validate_mindmodel.py --manifest .mindmodel/manifest.yaml --report reports/out.json || true
else
echo "No .mindmodel/manifest.yaml present — skipping validator"
fi
exit 0
- name: Upload mindmodel reports
if: ${{ always() }}
uses: actions/upload-artifact@v4
with:
name: mindmodel-reports
path: reports/mindmodel-report-*.json

@ -0,0 +1,26 @@
import os
try:
import yaml
_HAS_YAML = True
except Exception:
_HAS_YAML = False
def test_mindmodel_workflow_exists_and_parses():
path = os.path.join(".github", "workflows", "mindmodel-validation.yml")
assert os.path.exists(path), f"Workflow file {path} does not exist"
# Minimal parse: if PyYAML is available, try safe_load; otherwise do a token check
with open(path, "r", encoding="utf-8") as f:
content = f.read()
if _HAS_YAML:
data = yaml.safe_load(content)
assert data is not None and isinstance(data, dict)
assert "on" in data or "name" in data
else:
# fall back to simple checks to avoid introducing new deps
assert "name:" in content
assert "on:" in content
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